x^2+7x+52=0

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Solution for x^2+7x+52=0 equation:


Simplifying
x2 + 7x + 52 = 0

Reorder the terms:
52 + 7x + x2 = 0

Solving
52 + 7x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-52' to each side of the equation.
52 + 7x + -52 + x2 = 0 + -52

Reorder the terms:
52 + -52 + 7x + x2 = 0 + -52

Combine like terms: 52 + -52 = 0
0 + 7x + x2 = 0 + -52
7x + x2 = 0 + -52

Combine like terms: 0 + -52 = -52
7x + x2 = -52

The x term is 7x.  Take half its coefficient (3.5).
Square it (12.25) and add it to both sides.

Add '12.25' to each side of the equation.
7x + 12.25 + x2 = -52 + 12.25

Reorder the terms:
12.25 + 7x + x2 = -52 + 12.25

Combine like terms: -52 + 12.25 = -39.75
12.25 + 7x + x2 = -39.75

Factor a perfect square on the left side:
(x + 3.5)(x + 3.5) = -39.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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